Agenda for week 7: Dirac equation and spin
Learning goals:
- Connection between spin and angular momentum
- Non-relativistic limit of the Dirac equation
- Existence of antiparticles, many-body viewpoint
- Chirality, helicity
- Dirac equation in a classical electromagnetic field, first relativistic corrections
Reading assignment:
Notes for week 7: Dirac equation and spin
More details:
- Tuominen, Sec 9.2 (also 9.3, 9.5)
- Bransden & Joachain, Secs 15.4-15.7 (Note B&J use a pseudo-Euclidean metric, with 4-vectors that have an imaginary time component. This is horrible and you should avoid this at all costs)
- Sakurai & Napolitano, Secs 8.2,8.3
Preliminary exercises,
Do these during/after reading the assignment work. Will be discussed in class April 27th.
- Show, using the Pauli representation of Dirac matrices, that the spin and angular momentum operators do not commute with the free particle Hamiltonian, but the total angular momentum does.
- Using some explicit representation of the
matrices from week 6 check that
and that
are projection operators (what are the conditions required from a projection operator?).
- Derive the Pauli equation (which you remember from the A-part of the course) from the Dirac equation. Show that the gyromagnetic ratio of the electron is
.
Homework exercises, week 7
Will be discussed in the tutorial session on Thursday April 29th. Return a scanned pdf with your solution by Friday April 30th, at 9 pm using the form below. Then check and grade your solution with the help of the model solutions and resubmit your graded solutions by Tuesday May 4th at 9 am.
- Construct the positive energy helicity states, i.e. the eigenstates of
for a fixed momentum
as linear combinations of the plane wave solutions of the Dirac equation
constructed in week 6.
- You know from week 6 that the current
is conserved, i.e.
. Check this once again. What is
? This is known as the axial current. You know that
is special for
, how does this show up here?
- (Tuominen, 9.6.5) In the presence of an electromagnetic field, the Dirac Hamiltonian is (
)
- Derive the Heisenberg equation of motion for the kinetic momentum
. Compare to the classical equation of motion with a Lorentz force
- Derive the equation of motion for the helicity
This shows that the helicity is conserved not only in free motion, but also in a magnetic field, but not in an electric field.
- Derive the Heisenberg equation of motion for the kinetic momentum
- Look at the muon
paper Phys. Rev. Lett. 126, 141801
- What makes the muon
more interesting than the electron, for discovering beyond-the-standard model physics?
- What is the frequency (Hz) of the signal that is actually measured,
(
in Fig 2), corresponding to the actual anomalous magnetic moment?
- From the result for
, this frequency and the Lorentz
factor given in the paper calculate the cyclotron frequency (the inverse of the time for one rotation around the ring)
- Also another frequency
is measured, what is it and why is it measured?
- What makes the muon
- Consider an infinite one-dimensional wire with charged fermions. Assume we apply an electric field
perpendicular to the wire, and no magnetic field. Assume also that the wire is overall charge neutral, i.e.,
. This is realized for example in metals due to the presence of the positive-charge ions canceling the charge of the electrons. Let us consider the lowest-order relativistic corrections to the spectrum of the fermions. For a wire in the
direction, the Hamiltonian at low momenta (ignoring the correction scaling as
) is thus of the form
Find the energy spectrum
of the fermions.
Solutions are here.
Exercise points (filled by TA)
Please
Notes for week 7: Dirac equation and spin
Angular momentum and spin
The two-fold degeneracy of indicates that there must be another observable which commutes with
and
. The Hamiltonian is rotationally symmetric, so we might try the orbital angular momentum operator
which has the components
, but it is not a constant of motion:
in component notation
.
We define a spin-operator in the Dirac-Pauli representation as It can be readily justified by referring to the eigenstates of the Dirac equation in the rest frame. However, also spin by itself is not a good quantum number:
but the total angular momentum
commutes with
. Thus
and
is a constant of motion. This also means that
and
have common eigenstates.
and
are good quantum numbers. The form of the total angular momentum operator also shows that Dirac equation indeed describes spin-½ particles, as we have claimed.
Helicity
So we have seen that the spin and orbital angular momentum of a free particle are not constants of motion, i.e. are not conserved, even in free motion. Clearly such a nonconserved quantity is not an appropriate quantum number to describe the spin that is familiar from nonrelativistic physics.
However, we saw that the total angular momentum of a particle is a conserved quantity. If we want to have the interpretation of a "spin", it is useful to remember that classically the angular momentum vector is orthogonal to the momentum. This leads us to the component of the total angular momentum in the direction of the momentum, which is called helicity . The helicity does not have any "orbital angular momentum" in the classical sense. Thus it should only be made up by the intrinsic angular momentum. On the other hand, it is conserved, as all the components of the total angular momentum are. Thus the helicity can be interpreted as the spin. The helicity is defined as where the orbital angular momentum vanishes since
. The helicity operator has the same eigenvalues as the spin operator:
.
The complete set of eigenstates of Dirac Hamiltonian can be described by momentum , helicity
and the sign of energy
. (Exercise: write down the plane wave solutions with quantum numbers
,
and
.)
Fig: Eigenstates of the single-particle Dirac equation. The rotating arrows represent helicity/spin according to a right-hand rule.
Now you should be able to go back and do Question 1 in the preliminary exercises
Weyl fermions and chirality
Let us define the "fifth -matrix" as
where the naming convention dates back to a time when
was called
. The matrix
can be used to define the chirality or handedness of spinors.
Let us use to construct two complementary subspaces of spinors. The eigenvalues of
are
, so the projection operators to these subspaces are
As projection operators, they satisfy the relations
Some nomenclature: The 4-component spinors
we have been dealing with so far are called Dirac spinors. The 2-component spinors we obtain by using the projection operators on Dirac spinors,
and
, are left-handed and right-handed Weyl spinors, respectively.
Weyl representation
Transformations of and
are most easily discussed in the Weyl basis, in which the
-matrices are
By defining the "four-vectors"
and
, the
's can be described with one expression
In Weyl basis, the chiral projection operators are thus, in this basis, the upper and lower components of a Dirac spinor are the left-handed and right-handed projection of
, respectively:
Lorentz-transformations of left and right handed spinors
The fundamental difference which separates the left-handed and right-handed Weyl fermions from each other is that they belong to different representations of the Lorentz group. In other words, under the proper Lorentz transformations, they transform among themselves, but in different ways. In Weyl basis, they transform under rotation of angle around the axis
the same way,
but under boost of rapidity
to direction
, there is a sign difference:
In Weyl basis, the Dirac spinor transforms block-diagonally as
Let us now consider a parity transformation which inverts the sign of all the spatial coordinates. As
, this transformation is not part of the proper Lorentz group. The corresponding spinor transformation matrix commutes with
, but anticommutes with
's. Thus, it can be chosen as
and the wave function transforms as
Above, the explicit matrix form of
is given in the Weyl basis. In this basis, we easily see that the parity transformation mixes the left-handed and right-handed subspaces. If parity is a symmetry of the system, both left-handed and right-handed fermions must exist, which is of course suggested by the left/right nomenclature.
Dirac equations for left- and right handed states
The Dirac equation can be written in terms of and
as
The mass
now obtains a new interpretation; it is the coupling constant between the two fields. The energy gap between the particles and antiparticles is then another example of an avoided crossing. If
the fields do not couple and we obtain the Weyl equations
It used to be thought that neutrinos, which are spin-½ fermions, could be described by the Weyl equation. But neutrino oscillations suggest that neutrinos do have mass, so this leaves the Weyl equations without a realization in particle physics. In condensed matter, they do find a realization in the effective theory of Weyl semimetals. Even so, in the standard model, the Weyl fermions are -- in some sense -- more fundamental than Dirac fermions. In the electroweak part of the theory, there are interactions which only couple the left-handed particles. The corresponding interactions for the right-handed particles are absent from the theory. The parity symmetry is thus broken, and the standard model is naturally expressed in terms of Weyl fermions.
Chirality and helicity
Above, we defined helicity as the projection of spin along the momentum direction, which is one way of defining handedness. Does helicity then have some connection to chirality, which we also associate with some kind of handedness? The answer is that for massive particles, the two concepts are not the same: for example, chirality is Lorentz invariant, whereas helicity depends on the frame. Massive particles have velocity , so for them helicity can be inverted by a Lorentz boost which inverts the direction of momentum.
For massless particles, on the other hand, chirality and helicity coincide. The Weyl fermions are massless, so their states can also be described in terms of helicity. The left handed Weyl fermions (particles) have chirality -1 and helicity +1/2, which means that their spin is always antiparallel to momentum. Correspondingly, the spin of right handed Weyl fermions is parallel to momentum. The antiparticles of left and right handed particles have their spin parallel and antiparallel to momentum, respectively, i.e. just the opposite way as the particles.
Now you should be able to go back and do Question 2 in the preliminary exercises
Nonrelativistic limit
Note: In this section, we temporarily restore to the equations. We also return to use the Dirac representation of the Dirac matrices, see week 6
The non-relativistic limit is obtained when . At that limit, we can expand the dispersion as
Let us now consider the block matrix form of the Dirac equation The lower component can be solved in terms of the upper component as
The upper component obeys the equation
By defining the non-relativistic energy
and noticing that
, we obtain the Schrödinger equation for a spin-½ particle:
The lower component vanishes in the non-relativistic limit:
We conclude that in the non-relativistic limit and in the Dirac-Pauli representation, the upper components of the Dirac spinor describe spin-½ particles such as electrons.
Dirac equation with classical electromagnetic field
Note: Here we again restore to the equations.
How does the Dirac equation work in the presence of a classical electromagnetic field? In particular, we are interested in the relativistic corrections to the Pauli equation. Let us first derive the Pauli equation from the Dirac equation.
Maxwell's equations (with source terms) are The second and third equation are equivalent to a statement that
and
can be expressed in terms of a scalar potential
and a vector potential
as
In relativistic formulations of the electromagnetic field, the scalar and vector potentials are collected to a four-potential The field strength tensor for the EM field is
We note that
. The components are
where we used Maxwell's second and third equations.
With the electric current four-vector
Maxwell's first and fourth equations are expressed simply as
The proof is left as an exercise. In the derivation, the relation between the speed of light, vacuum permeability and the electric constant is needed:
.
Pauli equation
We would like to derive a generalization of the Schrödinger equation with the correct coupling to a classical electromagnetic field. The derivation is similar to the one that we did above in deriving the Schrödinger equation, now only a little more involved due to electromagnetic potentials.
Let us do the minimal substitution to the Dirac equation: where
is the charge of the particle (for electron
),
is the vector potential and
is the scalar potential. The Dirac Hamiltonian becomes
Notice that both the upper (particle) and lower (antiparticle) blocks couple to the EM field with the same charge
. But from the many-particle Hamiltonian we saw that the lower block actually describes an absence of an antiparticle (double negation), which suggests that the charge of the antiparticle must be
.
The covariant form of the minimal substitution is , where
.
Let us consider a case in which and
are time-independent. The stationary Dirac equation in the position basis,
, can be written in the Dirac-Pauli basis as two coupled equations for the 2-component spinors:
Let us introduce the canonical momentum operator
. The B-component can be solved as
Again
is of the order
. Substituting this into the upper equation, we find an equation for
where
and
We are interested in the non-relativistic limit , in which we can expand
as
Let us first consider the lowest order term, for which
. We then need to evaluate
where we used Pauli matrix identities to expand the square. Thus, at the non-relativistic limit, we obtain the Pauli equation:
where we changed the notation so that non-relativistic energy is
and the 2-component spinor
. The Pauli equation was originally formulated on phenomenological grounds by Wolfgang Pauli in 1927, before the discovery of the Dirac equation.
We should also verify that the wavefunction is correctly normalized up to a term of order :
Electron gyromagnetic ratio
The Zeeman term is the interaction energy of the magnetic dipole moment of a spin-½ particle with a magnetic field. The magnetic dipole moment operator can be written in the alternative forms:
the last of which contains
, the gyromagnetic ratio, i.e. the ratio between the magnetic moment
and the spin
. Why the
is defined this way is best understood by comparing the last version
to the magnetic moment of a classical particle with a fixed orbital angular momentum
. A calculation in classical electromagnetism (see e.g. Wikipedia) shows that a classical particle with angular momentum
has a magnetic moment
, i.e. a gyromagnetic ratio
, and thus a potential energy
.
The minimally substituted Dirac equation predicts that the electron has . One could say that an elecron spin interacts with a magnetic field twice as strongly (per unit of angular momentum) than an electron orbital angular momentum.
In fact the electron gyromagnetic ratio is not exactly . The deviation
is known as the anomalous magnetic moment. It is related to vertex corrections due to the electron's interaction with virtual photons, and can be calculated using quantum electrodynamics. The lowest order correction was found by Julian Schwinger in 1948:
where
is the fine-structure constant. Experimentally,
The electron magnetic moment is one of the most precisely measured quantities in nature, and also a great success for quantum electrodynamics; the theory and the experiments agree up to 10 digits!
Very recently a measurement of the analogous muon magnetic moment has raised a lot of attention. The measurement is made by circulating a spin-polarized beam of muons in a cyclotron. The rotation angular frequency, i.e. the inverse of the time to travel around the cyclotron ring, is determined by the combination , where
is the Lorentz
-factor associated with boosts to high velocity. On the other hand, the spin of the particle has a precessing motion given by a frequency
. The relative difference in frequencies is proportional to
, times a factor that is large for highly relativistic particles,
. By measuring the interference of these two frequencies one can do very precise measurements of
Relativistic corrections to the Pauli equation
Let us then find relativistic corrections of the order to the Pauli equation. Relativistic effects give the fine structure of the hydrogen spectrum. They are even more important in the description of the heavy elements in the periodic table, in which the electrons feel strong potentials (relativistic quantum chemistry). The color of gold is one example: without relativistic effects, gold would have a silvery color like most of the other metals.
To find all the corrections, we need to figure out the corrections both to the wavefunction-spinor and to the Hamiltonian . One correction arises from the normalization, another from the second order expansion for
We look for a non-relativistic 2-component spinor which satisfies the normalization condition
The upper component alone does not qualify at this order since there is a contribution from the lower component:
However, we can choose
as our non-relativistic spinor.
The equation of motion for can be found from the equation for
obtained in the previous section. To use it, we invert the above equation,
and substitute into the equation of motion (taking only the terms up to order
):
This is basically the equation of motion, but it still needs some massaging in order to get it in the form of a Schrödinger equation. This is done in the collapsible below.
Multiplying the above equation with from left, we obtain
where there are three terms of the form
. They also contain some higher order contributions, which are to be neglected. Let us adopt a shorthand
and
and write these terms as
Ignoring all the terms
and
, and rearranging most of the terms to the left-hand side, we arrive at
where we notice the structure
We need to compute these commutators. Because these are operators, we make them operate on a test function
, so that the scope of the derivative is easier to see.
The outer commutator is where the commutators evaluate to
and
Finally, the outer commutator evaluates to
The latter terms can also be written as
, since
where the term
vanishes since
is antisymmetric and
is symmetric in the swap
.
After all the algebra, we end up with Comparing with the Pauli equation above, we have
where the relativistic corrections to the Hamiltonian are
Let us now try to understand the physics of these various terms in a situation with only an electric potential. We set
, so that
,
and
.
Relativistic correction to the kinetic energy
The first term, is a correction to the kinetic energy, consistent with the series expansion of the relativistic dispersion relation
Spin-orbit interaction
The second term of the Hamiltonian is arguably the most interesting: The Hamiltonian
is known as the spin-orbit interaction. To understand the origin of this term, we go to the special case of central field
. The gradient is
and the cross product above becomes
where
is the orbital angular momentum operator. In terms of the spin angular momentum
, this part of the Hamiltonian can be written as
This coupling hybridizes spin and orbital angular momentum states, hence the name. The coupling between
and
has an important effect of breaking degeneracies of many systems, e.g. hydrogen; Because
and
, neither
nor
are good quantum numbers any more. Spin-orbit interaction also breaks degeneracies in crystals and enables many interesting condensed matter phenomena. As with other relativistic effects, spin-orbit interaction is stronger in the heavier elements of the periodic table.
Darwin term
The third term is known as the Darwin term:
For a point charge and
located at
, we can determine the potential
from the Poisson equation
which has a solution
We also set
so that the particle feels the attractive potential
The Darwin term in a central potential is The Darwin term only affects the energy of an s-orbital, since the wave function for other orbitals vanishes at the origin.
Now you should be able to go back and do Question 3 in the preliminary exercises
Existence of antiparticles and the many-body viewpoint
The Dirac equation has paradoxical properties when viewed as a single particle equation. A many-particle viewpoint (second quantization) is needed to resolve these issues.
In the many-body part of the course we saw how --- given a single particle Hamiltonian --- to transition from a single particle Hilbert space to a many-body Fock space. Here we do exactly the same. We find out that the solution to how to deal with the negative energy states is then the same as with the Fermi gas and its particle/hole excitations.
The Fock space Dirac Hamiltonian in position basis is where
is a 4-component column vector
and the field operators
create a particle at
with a spinorial index
, associated with particle/antiparticle and spin degrees of freedom. For example,
creates a particle with a wavefunction
, where the square root should be understood via some limit representation of the delta function.
The operators obey the anticommutation relations
We have in effect already diagonalized the many-particle Dirac Hamiltonian, as we have found the full set of single-particle eigensolutions. For a given momentum , we have two positive energy solutions, and two negative energy solutions with helicities
. The collapsible below contains some details of the diagonalization.
By making a Fourier transform, we can re-express the Hamiltonian as where
's are the Fourier transforms of the field operator spinors
These are not yet the annihilation operators for the eigenstates, as we still have the
matrix to diagonalize. In terms of the eigenspinors
,
, we have
where
for
and
for
. Here we choose to label the states by index
instead of helicity
, because of a more straightforward notation. We see that the Hamiltonian is diagonalized by the operators
with
. For convenience, we also define the operators
and
.
In terms of the eigenstates and their energies , the Fock space Hamiltonian is
The annihilation and creation operators
(for positive energy solutions) and
(for negative energy solutions) obey the anticommutation relations
The correspondence between the spinor solutions and the creation operators is
What is the ground state of this Hamiltonian? We can lower the energy by creating "negative-energy particles", so the ground state must be the one in which all the negative energy states are filled where
is the state quenched by all the annihilation operators:
. This state is known as the Dirac sea. It has the unpleasant property that the annihilation operator applied to the vacuum
no longer gives zero. In fact, applying
on the Dirac sea creates a hole, so that the energy of the system increases by
, charge decreases by
, momentum decreases by
and angular momentum decreases by
(in some direction). (Ex. Derive the total momentum and total angular momentum of operators according to the prescription given in the many-body part of the course and verify these claims!)
Fig: Charge conserving excitation of the Dirac sea. The thin/thick line denotes the empty/filled states. When a particle excitation is created, a negative energy hole is left behind. Minimum energy cost of this process is .
We can interpret this as a creation of an antiparticle with energy , momentum
, spin
and charge
. Let us define a new set of operators,
where both the spin and the momentum of the negative energy state are inverted. As their product, the helicity is not. The new operators obey the same anticommutation relations as the
-operators:
The inverse transformation from momentum space operators back to the field operators is
This is an example of a Bogoliubov transformation, which we first encountered on this course when diagonalizing the superconducting Bogoliubov-de Gennes Hamiltonian.
By rearranging the hole part Making a change of variables
under the integral, we get the Hamiltonian
with only positive energy excitations.
is an (infinite) constant energy shift, which does not affect the dynamics. With only positive energy excitations, the ground state
can be defined in the usual way as the state which is is quenched by all the annihilation operators:
The fermionic nature of the particles appears when we choose the anticommutation relations instead of commutation relations. The reason for the choice is simply that with bosonic operators we cannot invert the sign of antiparticle energies and consequently we are not able to define a proper ground state, i.e. with bosons, there is no Pauli repulsion and the Dirac sea cannot be filled.
Dirac predicted the existence of antiparticles in 1928, and positron, the antiparticle of electron, was discovered in 1933 by C.P. Anderson in cosmic radiation. As all the quantum numbers are inverted for the antiparticle, no conservation law (e.g. charge conservation) forbids the process in which particle and antiparticle annihilate each other, or the inverse one in which a particle-antiparticle pair pop into existence, as long as enough energy is provided.
Fig: Particle/antiparticle excitations of the many-body Dirac Hamiltonian. The rotating arrows represent helicity/spin according to a right-hand rule.
Apart from the negative energy solutions, there is also a more subtle reason to reject Dirac equation as a single-particle equation. In relativity, we can associate mass with energy, and consequently mass can be created. Furthermore, the Heisenberg uncertainty relation is not violated for a creation of particle-antiparticle pair out of vacuum, if that pair exists for a short enough time. The relativistic vacuum is then a highly dynamic entity, and can be pictured as a boiling sea of particle-antiparticle pairs appearing and disappearing all the time and interacting with each other. For this reason a relativistic theory cannot exist within a Hilbert space
with a fixed particle number
.
A consequence of this is that the expectation value for a space-like separation is non-zero (proportional to
). In single-particle picture it would seem as if the particle can travel faster than light. In many-body picture the effect can be interpreted as an entanglement of the vacuum. Relativity is not violated as the above correlation is of the Einstein-Podolsky-Rosen type and cannot transmit any information.
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